What will be the work done by a man weighning 40 kgf and holding a body of 20 kgf on his head and moving a distance of 10 m up an incline of 10 m up an incline of 1 in 5 (Take `g = 9.8 ms^(-2)`) ?

Explanation

To solve the problem, we need to calculate the work done by a man weighing 40 kgf while carrying a body of 20 kgf and moving up an incline of 10 m. The incline is given as 1 in 5, and we will use the value of g = 9.8 m/s².

### Step-by-Step Solution:

1. **Determine the Total Weight**:
The total weight (force due to gravity) the man is carrying is the sum of his weight and the weight of the body.
\[
\text{Weight of man} = 40 \text{ kgf}
...