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A force F = (10 +0.25x ) is acting on...

A force F = `(10 +0.25x )` is acting on a particle moving along positive X direction . Calculate the work done by this force during a displacement from x = 1 m to x = 4 m .

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To calculate the work done by the force \( F = (10 + 0.25x) \) during a displacement from \( x = 1 \, \text{m} \) to \( x = 4 \, \text{m} \), we will follow these steps: ### Step 1: Understand the Work Done Formula The work done \( W \) by a force when it acts on an object is given by the integral of the force over the displacement: \[ W = \int_{x_1}^{x_2} F \, dx \] where \( F \) is the force, \( x_1 \) is the initial position, and \( x_2 \) is the final position. ...
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