Two identical springs X and Y are compressed by the same amount. If X is stiffier than Y, in which spring more work has to be done?

Explanation

To solve the question, we need to understand the relationship between the work done on a spring and its spring constant. The work done on a spring when it is compressed or stretched can be calculated using the formula:

\[ W = \frac{1}{2} k x^2 \]

where:
- \( W \) is the work done,
- \( k \) is the spring constant,
- \( x \) is the amount of compression or extension.
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