The potential energy function for a particle executing linear SHM is given by `V(x)= 1/2kx^2` where k is the force constant of the oscillator. For `k = 0.5 Nm^(-1)`, the graph of V(x) versus x is shown in the figure A particle of total energy E turns back when it reaches `x=pmx_m`.if V and K indicate the potential energy and kinetic energy respectively of the particle at `x= +x_m`,then which of the following is correct?

Options

A. `V = 0,K = E`
B. `V = E,K = 0 `
C. `V lt E, K = 0 `
D. `V = 0 , K lt E`

Answer

B

Explanation

At ` x = + x_(m)` the particle velocity is zero , so kinetic energy K = 0 and whole energy is in the form of potential energy so V = E .