If the earth were made of iron of relative density 7.87, what would be the value of acceleration due to gravity on its surface ? Take, Radius of earth `= 6.37 xx 10^(6) m` , `G = 6.67 xx 10^(11) Nm^(2) kg^(-2)`

Explanation

To find the value of acceleration due to gravity on the surface of the Earth if it were made of iron with a relative density of 7.87, we can follow these steps:

### Step 1: Calculate the Density of Iron
The relative density (or specific gravity) of a substance is defined as the ratio of its density to the density of water. Given that the relative density of iron is 7.87, we can express the density of iron (ρ_iron) as:

\[ \rho_{\text{iron}} = 7.87 \times \rho_{\text{water}} \]
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