Two brass spheres of diameter 10 cm and 1 cm are placed with their centres 50 cm apart. If the relative density of brass is 8.5, calculate the gravitational attraction between the spheres. If the brass spheres are replaced by lead spheres (relative density greater than brass) of same radii, will the force of attraction increase or decrease ? For earth
Take `R = 6.37 xx 10^(8) cm`
Mean density `= 5.53 xx 10^(3) kg m^(-3)`

Explanation

To solve the problem of calculating the gravitational attraction between two brass spheres, we will follow these steps:

### Step 1: Determine the Masses of the Spheres
1. **Calculate the Density of Brass**:
The relative density of brass is given as 8.5. The density of water is \(1000 \, \text{kg/m}^3\).
\[ \text{Density of brass} = 8.5 \times 1000 = 8500 \, \text{kg/m}^3 \]
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