Considering the earth to be a perfect sphere of radius `6.4 xx 10^(6)m`, rotating about its axis with a period of 1 day `(= 8.64 xx 10^(4)s)`, calculate the difference in acceleration due to gravity at the poles and the equator.

Explanation

To solve the problem of calculating the difference in acceleration due to gravity at the poles and the equator, we will follow these steps:

### Step 1: Understanding the Formula
The acceleration due to gravity at any point on the surface of the Earth can be expressed as:
\[ g' = g - \omega^2 R \cos^2 \lambda \]
Where:
- \( g' \) is the effective acceleration due to gravity.
- \( g \) is the acceleration due to gravity (approximately \( 9.81 \, \text{m/s}^2 \)).
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