Home
Class 11
PHYSICS
The escape velocity on the surface of ea...

The escape velocity on the surface of earth is 11.2 km/s. If earth has mass 9 times the mass of Mars and radius equal to twice the radius of Mars, calculate the minimum velocity required by a projectile to escape the gravitational field of Mars.

Text Solution

AI Generated Solution

To find the minimum velocity required by a projectile to escape the gravitational field of Mars, we can use the relationship between the escape velocities of Earth and Mars, given the mass and radius of both planets. ### Step-by-Step Solution: 1. **Understand the escape velocity formula**: The escape velocity \( V_e \) from a celestial body is given by the formula: \[ V_e = \sqrt{\frac{2GM}{R}} ...
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    MODERN PUBLICATION|Exercise Practice Problems|31 Videos
  • GRAVITATION

    MODERN PUBLICATION|Exercise Conceptual Questions|19 Videos
  • MATHEMATICAL TOOLS

    MODERN PUBLICATION|Exercise PRACTICE PROBLEMS (10)|12 Videos

Similar Questions

Explore conceptually related problems

Escape velocity on the surface of earth is 11.2 km/s . Escape velocity from a planet whose mass is the same as that of earth and radius 1/4 that of earth is

If Earth has mass nine times and radius twice that of the planet Mars, calculate the velocity required by a rocket to pull out of the gravitational force of Mars. Take escape speed on surface of Earth to be 11.2km//s

The escape velocity of a body from the surface of the earth is V_(1) and from an altitude equal to twice the radius of the earth, is, V_(2) . Then

The escape velocity of the earth is 11.2 km/s. For a planet whose mass and radius are twice those of the earth, the escape velocity will be

The escape velocity on the surface of the earth is 11.2 kms^(-1) . If mass and radius of a planet is 4 and 2 tims respectively than that of the earth, what is the escape velocity from the planet?

If the mass of a Planet is eight times the mass of the earth and its radius is twice the radius of the earth, what will be the escape velocity for that planet ?