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A satellite revolves around a planet of ...

A satellite revolves around a planet of mean density `4.38 xx 10^(3)kg//m^(3)`, in an orbit close to its surface. Calculate the time period of the satellite.
Take, `G = 6.67 xx 10^(-11) Nm^(2) kg^(-2)`.

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AI Generated Solution

To calculate the time period of a satellite revolving around a planet of mean density \( \rho = 4.38 \times 10^{3} \, \text{kg/m}^{3} \), we can follow these steps: ### Step 1: Understand the relationship between gravitational force and centripetal force The gravitational force acting on the satellite provides the necessary centripetal force for its circular motion. The gravitational force \( F_g \) can be expressed as: \[ F_g = \frac{G M m}{r^2} \] ...
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