The gravitational potential at some point above the surface of the earth is `-4.32 xx 10^(7) J//kg` and acceleration due to gravity at that point is `5.4 m//s^(2)`. If the mean radius of earth is `6.37 xx 10^(6)m`, then find the height of this point from the earth's surface.

Explanation

To solve the problem, we need to find the height \( h \) of a point above the surface of the Earth given the gravitational potential and the acceleration due to gravity at that point.

### Step-by-Step Solution:

1. **Identify the given values:**
- Gravitational potential \( V = -4.32 \times 10^7 \, \text{J/kg} \)
- Acceleration due to gravity \( g = 5.4 \, \text{m/s}^2 \)
- Mean radius of the Earth \( R = 6.37 \times 10^6 \, \text{m} \)
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