Two particles P and Q of masses 2 kg and 4 kg initially at a distance of 2m from each other are released. If the particles move under mutual attraction, then find speed of particles P when speed of Q is 5 cm/hour. Also find the separation between these particles at this instant.

Explanation

To solve the problem step by step, we will follow these steps:

### Step 1: Understand the System
We have two particles P and Q with masses \( m_P = 2 \, \text{kg} \) and \( m_Q = 4 \, \text{kg} \) respectively, initially separated by a distance of \( d = 2 \, \text{m} \). They are released from rest and will move towards each other due to their mutual gravitational attraction.

### Step 2: Convert the Speed of Q
The speed of particle Q is given as \( 5 \, \text{cm/hour} \). We need to convert this speed into meters per second:

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