A body weighs 63 N on the surface of the earth. What is the gravitational force on it due to the earth at a height equal to half the radius of the earth ?

Explanation

Weight of the body = mg = 63 N
`h = (R )/(2)`
As we know `(g_(h))/(g) = (R^(2))/((R+h)^(2)) = (R^(2))/(R+(R )/(2))^(2)`
`g_(h) = (4)/(9)g`
Force at a height `h = mg_(h) = (4)/(9) xx mg = (4)/(9) xx 63`
= 28 N