A satellite `S_(1)` is revolving in a circular orbit of radius R around the earth. Another satellite `S_(2)` is revolving in an orbit of radius 2.02 R. By which percentage the period of satellite `S_(2)` will be longer than `S_(1)` ?

Explanation

To solve the problem of determining by what percentage the period of satellite \( S_2 \) is longer than that of satellite \( S_1 \), we can use Kepler's Third Law of planetary motion, which states that the square of the period of a satellite is directly proportional to the cube of the semi-major axis (or radius in the case of circular orbits) of its orbit.

### Step-by-Step Solution:

1. **Identify the Given Information:**
- Radius of satellite \( S_1 \): \( R \)
- Radius of satellite \( S_2 \): \( 2.02R \)

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