The time period of a simple pendulum is `T_(1)` on the surface of earth. If taken to a height 2 R above the surface of earth, the time period becomes `T_(2)`. What will be the value of `T_(1)//T_(2)` ? (R is the radius of earth).

Explanation

To solve the problem, we need to find the ratio of the time periods of a simple pendulum at two different heights: on the surface of the Earth and at a height of \(2R\) above the surface of the Earth.

### Step-by-Step Solution:

1. **Understand the formula for the time period of a simple pendulum**:
The time period \(T\) of a simple pendulum is given by the formula:
\[
T = 2\pi \sqrt{\frac{L}{g_{\text{effective}}}}
...