At what height above the surface of earth, the acceleration due o to gravity of earth ? Radius by 51% of its value on the surface of earth ? Redius of earth = 6,400 km.

Explanation

`g. = 100 - 51 = 49% = (49)/(100)g`
`(49)/(100)g = (gR^(2))/((R+h)^(2))`
`(7)/(10) = (R )/(R + h)`
`7R + 7h = 10 R`
`7h = 3R`
`h = (3)/(7)R = (3)/(7) xx 6,400 = 2,742.8 km`