The mass of Saturn is 95 times that of earth and radius is 9.5 times the radius of earth. What will be escape velocity on the surface of saturn if the escape velocity on earth's surface is `11.2 kms^(-1)` ?

Explanation

To find the escape velocity on the surface of Saturn, we can use the formula for escape velocity, which is given by:

\[ v_e = \sqrt{\frac{2GM}{R}} \]

Where:
- \( v_e \) is the escape velocity,
...