A spherical planet far out in space has a mass `M_(0)` and diameter `D_(0)`. A particle of mass m falling freely near the surface of this planet will experience an accelertion due to gravity which is equal to

Options

A. `4 GM_(p) mu//D_(p)^(2)`
B. `4 GM_(p)//D_(p)^(2)`
C. `GM_(p) mu//D_(p)^(2)`
D. `GM_(p)//D_(p)^(2)`

Answer

B

Explanation

`F = mg. = (GM_(P)m)/(R^(2))`
`mg. = (GM_(P)m)/((D_(P))/(2^(2))) = (4 GM_(P)m)/(D_(P)^(2))`
`g . = (5GM_(P))/(D_(P)^(2))`