Ethanol on treatment with cone, `H_(2) SO_(4)` at 443 K gives ethene/ethoxyethane.

Explanation

To solve the problem of what happens when ethanol is treated with concentrated sulfuric acid at 443 K, we can break down the process step by step.

### Step-by-Step Solution:

1. **Identify the Reactants:**
- The reactant given is ethanol, which has the chemical formula \( \text{C}_2\text{H}_5\text{OH} \) or \( \text{CH}_3\text{CH}_2\text{OH} \).

2. **Understand the Role of Concentrated Sulfuric Acid:**
...