Complete the reaction:
`C_(2)H_(5)OC_(2)H_(5)+2HI overset(373K) to ?`

Explanation

To complete the reaction of diethyl ether with hydroiodic acid (HI), we can follow these steps:

1. **Identify the Reactants**: The reactants are diethyl ether (C2H5OC2H5) and hydroiodic acid (HI). Diethyl ether consists of two ethyl groups (C2H5) connected by an oxygen atom.

2. **Determine the Reaction Conditions**: The reaction is carried out at 373 K with 2 moles of HI. Since HI is in excess, it will react completely with the diethyl ether.

3. **Reaction Mechanism**: When diethyl ether reacts with HI, the ether oxygen atom (O) is protonated by the hydrogen ion (H+) from HI. This forms a positively charged intermediate.

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