The IUPAC name of ` CH_3 CH_2 - overset(O ) overset(||)C-CH_2-overset(O ) overset(||)C-H ` is

Options

A. 1-oxopentanal-3-one
B. 1-oxopentanal
C. 3-oxopentanal
D. 3-oxopentanal-3-one

Answer

To determine the IUPAC name of the compound `CH3CH2-C(=O)-CH2-C(=O)-H`, we will follow these steps:

### Step 1: Identify the Functional Groups
The compound contains two carbonyl groups (C=O) and one aldehyde group (C=O at the end of the chain). The presence of these functional groups indicates that we are dealing with a ketone and an aldehyde.

### Step 2: Count the Carbon Atoms
Count the total number of carbon atoms in the longest continuous chain. In this case, we have:
- CH3 (1 carbon)
- CH2 (1 carbon)
- C(=O) (1 carbon)
- CH2 (1 carbon)
- C(=O) (1 carbon)
- H (not counted as a carbon)

This gives us a total of 5 carbon atoms.

### Step 3: Determine the Main Chain
The longest carbon chain that includes both carbonyl groups is 5 carbons long. Therefore, the base name will be derived from pentane.

### Step 4: Identify the Position of the Functional Groups
The ketone functional groups (C=O) are located at the 3rd carbon of the chain. The aldehyde group is at the end of the chain.

### Step 5: Assign the Correct Prefixes
Since we have two carbonyl groups, we will use the prefix "oxo" to indicate their presence. The aldehyde group takes precedence in naming, so we will indicate its position as well.

### Step 6: Combine the Information
Putting all the information together, we have:
- The main chain is pentane.
- There is an aldehyde at position 1.
- There is a ketone (oxo) at position 3.

Thus, the IUPAC name of the compound is **3-Oxopentanal**.

### Final Answer:
The IUPAC name of `CH3CH2-C(=O)-CH2-C(=O)-H` is **3-Oxopentanal**.

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