Acetic acid is reduced with `LiAIH_4` to give

Options

A. `CH_3CH_2 OH `
B. `CH_3 CHO`
C. `CH_3 CH_3`
D. `CH_3 OH `

Explanation

To solve the question of what product is formed when acetic acid is reduced with lithium aluminum hydride (LiAlH4), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactant:**
- The reactant is acetic acid, which has the chemical formula \( CH_3COOH \).

2. **Understand the Reducing Agent:**
- Lithium aluminum hydride (LiAlH4) is a strong reducing agent. It is capable of reducing carboxylic acids to their corresponding alcohols.

3. **Determine the Reduction Process:**
- When acetic acid is treated with LiAlH4, the carboxylic acid functional group (\(-COOH\)) is reduced to a primary alcohol. The reduction involves the conversion of the carbonyl group (\(C=O\)) of the acid to a hydroxyl group (\(-OH\)).

4. **Identify the Corresponding Alcohol:**
- Since acetic acid has two carbon atoms, the corresponding alcohol formed will also have two carbon atoms. The reduction of acetic acid will yield ethanol, which has the formula \( CH_3CH_2OH \).

5. **Write the Final Reaction:**
- The overall reaction can be summarized as:
\[ CH_3COOH + LiAlH_4 \rightarrow CH_3CH_2OH \]
- Therefore, the product of the reduction of acetic acid with lithium aluminum hydride is ethanol.

### Final Answer:
The product formed when acetic acid is reduced with lithium aluminum hydride is **ethanol** (\( CH_3CH_2OH \)).

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