In the reaction :
`CH_3 COOH overset(Ca(OH)_2) to A overset("Heat") to B overset("NH_2 OH) to C ,` C is

Options

A. `CH_3 COO NH_4`
B. `CH_3 CH_2 CH = NOH `
C. `(CH_3)_2=NOH `
D. `CH_3 CONH_2`

Explanation

To solve the given reaction step by step, let's break down the process:

1. **Starting with Acetic Acid**: The initial compound is acetic acid, which is represented as \( \text{CH}_3\text{COOH} \).

2. **Reaction with Calcium Hydroxide**: When acetic acid reacts with calcium hydroxide \( \text{Ca(OH)}_2 \), it forms a calcium salt of acetic acid. The reaction can be represented as:
\[ 2 \text{CH}_3\text{COOH} + \text{Ca(OH)}_2 \rightarrow \text{(CH}_3\text{COO)}_2\text{Ca} + 2 \text{H}_2\text{O} \]
Here, \( A \) is \( \text{(CH}_3\text{COO)}_2\text{Ca} \) (calcium acetate).

3. **Heating A to form B**: When we heat the calcium acetate \( \text{(CH}_3\text{COO)}_2\text{Ca} \), it undergoes a process called pyrolysis, which leads to the formation of acetone \( \text{CH}_3\text{COCH}_3 \) and calcium carbonate. The reaction can be simplified as:
\[ \text{(CH}_3\text{COO)}_2\text{Ca} \xrightarrow{\text{Heat}} \text{CH}_3\text{COCH}_3 + \text{CaCO}_3 \]
Here, \( B \) is \( \text{CH}_3\text{COCH}_3 \) (acetone).

4. **Reaction of B with Hydroxylamine**: The next step involves the reaction of acetone \( \text{CH}_3\text{COCH}_3 \) with hydroxylamine \( \text{NH}_2\text{OH} \). This reaction leads to the formation of an oxime. The reaction can be represented as:
\[ \text{CH}_3\text{COCH}_3 + \text{NH}_2\text{OH} \rightarrow \text{CH}_3\text{C(=N-OH)}\text{CH}_3 + \text{H}_2\text{O} \]
Here, \( C \) is \( \text{CH}_3\text{C(=N-OH)}\text{CH}_3 \) (acetone oxime).

### Final Answer:
Thus, the final product \( C \) is acetone oxime, represented as \( \text{CH}_3\text{C(=N-OH)}\text{CH}_3 \).

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