Glucose on treatment with sodium amalgam gives

Options

A. n-heptanoic acid
B. Sorbitol
C. gluconic acid
D. glucaric acid

Explanation

To solve the question "Glucose on treatment with sodium amalgam gives," we will follow these steps:

### Step 1: Understand the Structure of Glucose
Glucose is a simple sugar (monosaccharide) with the molecular formula C6H12O6. It contains an aldehyde group (-CHO) and several hydroxyl groups (-OH). The structure can be represented as follows:

- Aldehyde group: -CHO
- Hydroxyl groups: -OH (attached to various carbon atoms)

### Step 2: Identify the Reactant
When glucose is treated with sodium amalgam (Na/Hg), sodium acts as a reducing agent. Sodium amalgam is a mixture of sodium and mercury, and it is commonly used in organic chemistry for reduction reactions.

### Step 3: Determine the Reaction
In this reaction, the aldehyde group (-CHO) of glucose is reduced to a primary alcohol (-CH2OH). This reduction process converts glucose into sorbitol.

### Step 4: Write the Product
After the reduction of glucose, the product formed is sorbitol, which has the following structure:

- Sorbitol structure:
- All carbon atoms will have -CH2OH groups instead of the aldehyde group.
- The structure will look like this:

```
CH2OH
|
HO-CH
|
HO-CH
|
HO-CH
|
HO-CH
|
CH2OH
```

### Conclusion
Thus, when glucose is treated with sodium amalgam, the product formed is **sorbitol**.

### Final Answer:
Glucose on treatment with sodium amalgam gives **sorbitol**.

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