Glucose on oxidation with bromine water gives

Options

A. gluconic acid
B. tartaric acid
C. saccharic acid
D. mesooxalic acid

Explanation

To determine the product of glucose when it is oxidized with bromine water, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Structure of Glucose**:
Glucose is an aldohexose sugar with the molecular formula C₆H₁₂O₆. Its structure includes an aldehyde group (-CHO) at one end and multiple hydroxyl groups (-OH) attached to the carbon chain.

2. **Understand the Role of Bromine Water**:
Bromine water (Br₂ in water) is a weak oxidizing agent. It can oxidize aldehyde groups to carboxylic acids but does not affect alcohol groups under mild conditions.

3. **Oxidation of the Aldehyde Group**:
When glucose is treated with bromine water, the aldehyde group (-CHO) at the first carbon is oxidized to a carboxylic acid (-COOH). This reaction converts glucose into gluconic acid.

4. **Write the Product**:
The structural formula of gluconic acid can be represented as:
- C₆H₁₂O₆ (glucose) → C₆H₁₂O₇ (gluconic acid)

5. **Conclusion**:
Therefore, the product of glucose on oxidation with bromine water is gluconic acid.

### Final Answer:
Glucose on oxidation with bromine water gives gluconic acid.

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