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Which of the following statement(s) is(a...

Which of the following statement(s) is(are) true?

A

The two six-membered cyclic hemiacetal forms of D-(+)-glucose are called anomers.

B

Hydrolysis of sucrose gives dextrorotatory glucose and laevorotatory fructose.

C

Monosaccharides cannot be hydrolysed to give polyhydroxy aldehydes and ketones.

D

Oxidation of glucose with bromine water gives glutamic acid.

Text Solution

AI Generated Solution

The correct Answer is:
To determine which statements are true regarding the properties of D-glucose and related compounds, we will analyze each statement one by one. ### Step-by-Step Solution: 1. **Statement 1**: "The two 6-membered cyclic hemiacetal forms of D-glucose are called anomers." - **Analysis**: This statement is true. D-glucose can exist in two cyclic forms (α and β) due to the formation of a hemiacetal. These two forms differ in the configuration of the hydroxyl group (-OH) at the anomeric carbon (C1). When the -OH group is below the plane of the ring, it is called α-D-glucopyranose, and when it is above, it is called β-D-glucopyranose. Therefore, they are indeed anomers. 2. **Statement 2**: "Hydrolysis of sucrose gives dextrorotatory glucose and levorotatory fructose." - **Analysis**: This statement is also true. When sucrose undergoes hydrolysis, it breaks down into glucose and fructose. Glucose is dextrorotatory (rotates plane-polarized light to the right), while fructose is levorotatory (rotates plane-polarized light to the left). The resulting mixture is known as invert sugar, as the optical rotation changes from positive to negative. 3. **Statement 3**: "Monosaccharides cannot be hydrolyzed to give polyhydroxy aldehydes and ketones." - **Analysis**: This statement is true. Monosaccharides are the simplest form of carbohydrates and cannot be hydrolyzed further into simpler sugars or polyhydroxy compounds. They are already in their most basic form and do not undergo hydrolysis. 4. **Statement 4**: "Oxidation of glucose with bromine water gives glutamic acid." - **Analysis**: This statement is false. The oxidation of glucose with bromine water results in gluconic acid, not glutamic acid. Glutamic acid is an amino acid, while gluconic acid is a sugar acid derived from glucose. ### Conclusion: Based on the analysis: - **True Statements**: 1, 2, and 3. - **False Statement**: 4. Thus, the true statements are **1, 2, and 3**.

To determine which statements are true regarding the properties of D-glucose and related compounds, we will analyze each statement one by one. ### Step-by-Step Solution: 1. **Statement 1**: "The two 6-membered cyclic hemiacetal forms of D-glucose are called anomers." - **Analysis**: This statement is true. D-glucose can exist in two cyclic forms (α and β) due to the formation of a hemiacetal. These two forms differ in the configuration of the hydroxyl group (-OH) at the anomeric carbon (C1). When the -OH group is below the plane of the ring, it is called α-D-glucopyranose, and when it is above, it is called β-D-glucopyranose. Therefore, they are indeed anomers. 2. **Statement 2**: "Hydrolysis of sucrose gives dextrorotatory glucose and levorotatory fructose." ...
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