charges of an electron in esu determined as ` 4.806 xx 10^(-10) ` esu. Show that 1C `= 3xx 10 ^(9) ` esu

Explanation

a . `1C =3xx10 ^(9) esu " " because lesu (1)/( 3xx10 ^(9) C `
Number of electron in 1C =` 6.25 xx 10 ^(12) `
` because ` Number of electron in 1 esu ` = (1)/( 3xx10 ^(9)) xx 6.25 xx 10 ^(18) - 208 xx10 ^(9) `
Number of electrons in 1 esu ` = (1)/( 3xx10 &(9) ) xx 6.25 xx10 ^(18) `
` because ` charges esu is ` 6.25 xx10 ^(6) xx 4.806 xx10 ^(10) `
` therefore 1C =6.25 xx10 ^(18) xx 4.806 xx 10 ^(10) = 3xx 10 ^(9) ` esu of charges.