Three charges +4q . Q and +q are placed along a straight line of length 'a' at points 0, `( a)/(2) ` and a respectively . Find the relation between Q and q in order to make the net force on q to be zero For the net force q to be zero.

Explanation

` F_(CA) +F_(CB) =0`
ie. ` (1)/( 4pi in _0) (q.2q)/( a^(2) +(1)/( 4pi in -0)) (qQ)/((a)/(2)^(2)) =0
`2q +4Q =0 therefore Q= (-q)/( 2) `
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