The area of each plate of a parallel capacitor is `100 cm^(2)` and the distance between them is 0.05 cm. It is filled with a dielectric and its capacitance becomes `3.54 xx 10^(-4) muF`. Find the dielectric constant of the substance.

Explanation

Data supplied,
`A=100 cm^(2)=100 xx 10^(-4) m^(2)`
`C=3.54 xx 10^(-4) muF= 3.54 xx 10^(-4) xx 10^(-6) F =3.54 xx 10^(-10) F`
`d=0.05 cm =0.05 xx 10^(-2)m " "epsi_(0) =8.854 xx C^(-12) C^(2) N^(-1) m^(-2)`
`C=(epsi_(0) KA)/(d) " "K=(Cd)/(epsi_(0) A)=(3.54 xx 10^(-10) xx 0.05 xx 10^(-2))/(8.854 xx 10^(-12) xx 100 xx 10^(-4)) K=2`