Calculate the binding energy per nucleon of `""_3^7Li (7 u)`, Given mass of a proton = 1.007825 u and mass of neutron = `1.008665u`.

Explanation

Mass of 3 proton = `3 xx 1.007825 = 3.023475 u`
Mass of 4 neutrons = `4 xx 1.008665 = 4.03466 u`
Total mass = 7.058135 u
Mass of `""_3^7Li = 7.0878 u`
`:.` Mass defect = `0.029665 u`
Binding energy = `0.029665 xx 931 MeV = 27.618 MeV`
`:.` Binding energy per nucleon = `3.945 MeV`.