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The mass of ""(17)^(35)Cl is 34.9800 u ....

The mass of `""_(17)^(35)Cl` is `34.9800 u` . Calculate its binding energy per nucleon.

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The correct Answer is:
8.2 MeV
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Knowledge Check

  • The mass of a ""_(3)^(7)Li nucleus is 0.042u less than the sum of the masses of all its nucleons. The binding energy per nucleon of ""_(3)^(7)Li nucleus is nearly

    A
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    B
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    B
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    D
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  • The mass of a ""_(3)^(7)"Li" nucleus is 0.042 u less than the sum of the masses of all its nucleons. The binding energy per nucleon of ""_(3)^(7)"Li" nucleus is nearly

    A
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    B
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    D
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