For a CE- transistor amplifier , the audio signal voltage across the collected resistance of `2 k Omega` is 2 V . Suppose the current amplification factor of the transistor is 100 , find the input signal voltage and base current , if the base is `1 k Omega`.

Explanation

`V_(o) - 2V , R_(C) = 2 k Omega = 2000 Omega , I_(B) = ? , V_(i) = ? , r_(i) = 1 k Omega beta = 100`
`V_(o) = I_(C) xx R_(C) , I_(C) = (V_(B))/(R_(C)) = (2)/(2000) = 10^(-3) A = 1 m A`
`A_(V) = (V_(o))/(V_(C)) = beta ((R_(C))/(r_(i)))`
`V_(i) = V_(o) , (r_(i))/(beta R_(C)) = (2 xx 1)/(100 xx 2) = 0.01 V `
`beta = (I_(C))/(I_(B)) , I_(B) = (I_(C))/(beta) = (1)/(100) = 10^(-2) mA`