What is the dimensional formula of forc...

What is the dimensional formula of force ?

`[M LT^(-3)]`

`[M L^(2)T^(-2)]`

`[M L^(2)T^(-3)]`

`[M LT^(-2)]`

Text Solution

Verified by Experts

force = mass `xx `acceleration
Unit of force =unit of maxx `xx`unit of acceleration =unit of mass `xx. ("unit of length")/(("unit of time")^(2))`
Dimensional formula = `[M L T^(-2)]`

Topper's Solved these Questions

MEASUREMENTS
PEARSON IIT JEE FOUNDATION|Exercise very short answer type question|30 Videos
MEASUREMENTS
PEARSON IIT JEE FOUNDATION|Exercise Shor answer type Question|14 Videos
MAGNETISM
PEARSON IIT JEE FOUNDATION|Exercise Level-3|10 Videos
MODERN PHYSICS
PEARSON IIT JEE FOUNDATION|Exercise Level 3|5 Videos

In the following dimensionally correct equation F=(X)/("Linear Density") , where F is the force. What is the dimensional formula for X?

`M^(0)L^(0)T^(0)`

`M L T^(-2)`

`M^(2)L^(-2)T^(-2)`

`M^(2)L^(0)T^(-2)`

The damping force acting on an oscillating body is proportional to its velocity i.e. F = Kv. What is the dimensional formula for K?

`[M^(1)L^(1)T^(-1)]`

`[M^(1)L^(0)T^(-1)]`

`[M^(0)L^(1)T^(-2)]`

`[M^(1)L^(0)T^(1)]`

The viscous force acting on a body moving through a liquid is proportional to its velocity. What is the dimensional formula for the constant of proportional to its velocity. What is the dimensional formula for the constant of proportionality?

`[M^(1)L^(1)T^(-1)]`

`[M^(1)L^(1)T^(-2)]`

`[M^(1)L^(0)T^(-1)]`

`[M^(0)L^(1)T^(-1)]`