When the jaws of a vernier callipers are closed the 0th division of its vernier scale is to the right of the zero of the main scale and the V.S.D is 6 .Find the correction to be made to the observed measurement (take its least count as 0.1 mm)

Explanation

The vernier coincidence ,n=6
Zero error =V.S.D `xx`L.C
`=6xx 0.1 mm=0.6` and the error is positive .Thus the correction =-0.6 mm