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A wooden plank immerses upto 50% in wate...

A wooden plank immerses upto `50%` in water. Then what percentage of its volume is immersed in a liquid of density `0.5"g cm"^(-3)` ?

Text Solution

Verified by Experts

`100%`
weight of the floating body = weight of the displaced liquid
`V_(b)*d_(b)*g=V_(dt)*d_(t)*g`
`V_(b)*d_(b)*"g"(V_(b))/(2)*d_(w)*g(becaused_(w)=1"g cm"^(-3))`
`rArrd_(b)=0.5" g cm"^(-3)`
`V_(b)*((1)/(2))g=V_(dl)*(0.5)grArrV_(dt)=V_(b)`
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