A cauboid of volume `20 mxx 10 m xx 5m` has density `3 kg m^(-3)` .Find the maximum pressure exerted by cuboid on the surface .

Answer

600 Pa

Explanation

Density `= 3 kgm^-3`
Volume of cuboid `=1xxbxxh= 20 xx 10xx5 = 10^3 m^3`
Mass of cuboid
`="Density " xx "volume "`
`==3xx 10^3` kg
Weight of cuboid
`=mg = 3 xx 10^4 N`
`A_1= 200m ^2, A_2= 50m^2 `
`A_3= 100m^2`
Pressue `alpha 1/"Area"` that means the prosition of cuboid to give maximumbottom pressure is
`p=(3xx10^4)/(50)=0.6 xx 10^3= 600 pa`