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The equation of the circle having x-y-2=...

The equation of the circle having `x-y-2=0` and `x-y+2=0` as two tangents and `x-y=0` as a diameter is

A

`x^(2)+y^(2)+2x-2y+1=0`

B

`x^(2)+y^(2)-2x+2y-1=0`

C

`x^(2)+y^(2)=2`

D

`x^(2)+y^(2)=1`

Text Solution

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The correct Answer is:
C
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