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If n=|(2020), then 1/(log(2)n)+1/(log...

If `n=|__(2020)`, then
`1/(log_(2)n)+1/(log_(3)n)+1/(log_(4)n)+………..+1/(log_(2020)n)=`

A

`|__(2020)`

B

0

C

2020

D

1

Text Solution

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The correct Answer is:
D
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