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(3x + 1)/(( x- 1) (x - 3)) = (A)/(x - 1)...

`(3x + 1)/(( x- 1) (x - 3)) = (A)/(x - 1) + (B)/(x - 3)` , then `sin^(-1) (A)/(B)` =

A

`(pi)/(4)`

B

`(pi)/(2)`

C

`(pi)/(3)`

D

`(pi)/(6)`

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