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If f : R to R is defined by f (x) = 2x +...

If `f : R to R` is defined by f (x) = `2x + 3` , then `f^(-1) x`

A

does not exist because 'f' is not surjective

B

is given by `(x - 3)/(2)`

C

is given by `(1)/(2x + 3)`

D

does not exist because 'f' is not injective

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