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In an ammeter 10% of main current is pas...

In an ammeter 10% of main current is passing through the galvanometer. If the resistance of the galvanometer is G, then the shunt resistance, in ohms is

A

9G

B

`G//9`

C

`90G`

D

`G//90`

Text Solution

Verified by Experts

The correct Answer is:
b
`S=(I_(g)G)/(I-I_(g))`
`AsI_(g)=(1)/(10)I(give)`
`:.S=(I)/(10)xx(G)/((I-(I//10)))=(G)/(9)`
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