In an experiment with sonometer a tuning fork of frequency 256 Hz resonates with a length of 25 em and another tuning fork resonates with a length of 16 cm. Tension of the string remaining constant the frequency of the second tuning fork

Options

A. `163.84 Hz`
B. `400 Hz`
C. `320 Hz`
D. `204.8 Hz`

Answer

c

Explanation

In case of sonometer frequency is given by
`upsilon=(1)/(2l)sqrt((T)/(mu))`
where u is the mass per unit length
:.`upsilon_(2)/(upsilon_(1))=(I_(1))/(l_(2))impliesupsilon=(25)/(16)xx256=400Hz`