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The electric flux Gaussian for surface A...

The electric flux Gaussian for surface A that enclose the charged particles in free space is (given `q_1 =- 14 nC , q_2 = 78.85 nc ,q_3 =- 56 n C`

A

`10^(3) Nm^(2) C^(-1)`

B

`10^(3) CN^(-1)'m^(-2)`

C

`6.32 xx 10^(3) Nm^(2) C^(-1)`

D

`6.32 xx 10^(3) CN^(-1)m^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
a

Flux is due to charges enclosed per `epsilon_(0)`
`:. Total flux = (-14 + 78.85 - 56)nC//epsilon_(0)`
`=8.85xx10^(-9)Cxx(4pi)/(4piepsilon_(0))=8.85xx10^(-9)xx9xx10^(9)xx4pi`
`=1000.4Nm^(2)//C.i.e.1000Nm^(2)C^(-1)`
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