The dimensions of 'resistance' are same as those of . . . . . . . . . Where h is the Planck's constant e is the charge .

Options

A. `(h^(2))/(e^(2))`
B. `(h^(2))/(e )`
C. `h/(e^(2))`
D. `(h)/( e)`

Answer

C

Explanation

Resistance `=("Potential difference")/("Current")`
`["Resistance"]=([ML^(2)T^(-3)A^(-1)])/([A])=[ML^(2)T^(-3)A^(-2)]`
`[(h)/(e^(2))]=([ML^(2)T^(-1)])/([AT]^(2))=[ML^(2)T^(-3)A^(-2)]`