If the linear momentum of a body is increased by `50%` then the kinetic energy of that body increases by

Options

A. `10%`
B. `125%`
C. `225%`
D. `25%`

Answer

B

Explanation

Kinetic energy of the body, `K=(p^(2))/(2m)`
where p is the linear momentum and m is the mass of the body.
Since mass remains constant
`:." "Kprop p^(2)`
As `p.=p+(50)/(100)p=(3)/(2)p" ":.(K.)/(K)=((p.)/(p))^(2)=((3)/(2))^(2)=9/4`
`%` increases in the kinetic energy `=(K.-K)/(K)xx100`
`((K.)/(K)-1)xx100=(9/4-1)xx100=125%`