A chemical reaction was carried out at 300 K and 280 K. The rate constants were found to be `k_(1)` and `k_(2)` respectively . Then

Options

A. `K_(2)~~0.25K_(1)`
B. `K_(2)~~0.5K_(1)`
C. `K_(2)~~4K_(1)`
D. `K_(2)~~2K_(1)`

Answer

A

Explanation

A chemical reaction was carried out at 300K and 280 K.
for every `10^(@)` rise in temperature, the rate of the reaction becomes nearly double.
`Ato`product.
At 300K, `"rate"_(1)=K_(1)[A_(1)]`
At 280K, `"rate"_(2)=K_(2)[A_(2)]`
Temperature coefficient`=(K_(290))/(K_(280))=2`.
`K_(1)~~4K_(2) thereforeK_(2)=(1)/(4)K_(1)~~0.25K_(1)`
`K_(2)~~0.25K_(1)`.