In the case of a radio isotope the value of `T_(1//2) and lamda` are identical in magnitude. The value is

Options

A. 0.693
B. `(0.693)^(1//2)`
C. `1//0.693`
D. `(0.693)^(2)`

Answer

B

Explanation

For a radioisotope,
half-life period, `T_(1//2)=0.696//lamda`
Since `T_(1//2)=lamda` (given), `T_(1//2)^(2)=0.693`
`impliesT_(1//2)=0.693^(1//2)`.
Then value of `T_(1//2)` on `lamda` is `0.693^(1//2)`.