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The volume of water to be added N/2 HCl ...

The volume of water to be added `N/2` HCl to prepare `500cm^(3)` of `(N)/(10)` solution is

A

`450cm^(3)`

B

`100cm^(3)`

C

`45cm^(3)`

D

`400cm^(3)`

Text Solution

Verified by Experts

The correct Answer is:
D
As `N_(1)V_(1)=N_(2)V_(2)`
`(N)/(2)xxV=(N)/(10)xx500`
V=100 `cm^(3)`
From 100ml of `(N)/(2)HCl` to 500 ml `(N)/(10)HCl`
water added=500-100=400ml.
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