The number of `alpha and beta` particles emitted during the transformation of `""_(90)Th^(232)` to `""_(82)Pb^(208)` are respectively

Options

A. 4,2
B. 2,2
C. 8,6
D. 6,4

Answer

D

Explanation

`""_(90)Th^(232)to""_(82)Pb^(208)`
Loss in weight=232-208=24.
Hence number of `alpha`-particles emitted=`(24)/(4)=6`
Therefore,
`""_(90)Th^(232) underset(-6a)to""_(78)X^(208) underset(-4beta)to""_(82)Pb^(208)`
For increasing atomic no. by four units `4beta` particle must be emitted.