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In triangle ABC, /C=90^@ then (a^2-b^2)/...

In triangle `ABC`, `/_C=90^@` then `(a^2-b^2)/(a^2+b^2)=`

A

`sin (A +B)`

B

`sin (A-B)`

C

`cos (A +B)`

D

`sin ((A -B)/(2))`

Text Solution

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The correct Answer is:
B
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DISHA PUBLICATION-TRIGONOMETRIC FUNCTIONS -EXERCISE-1
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  9. If pn = cos^n theta + sin^n theta then pn - p(n-2) = k p(n-4) where k

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