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The sum of the coefficients in the expan...

The sum of the coefficients in the expansion of `(x^(2)- (1)/( 3))^(199) xx ( x^(3) + ( 1)/( 2))^(200)` is

A

`1//3`

B

`-1//3`

C

`2//3`

D

`3//2`

Text Solution

AI Generated Solution

The correct Answer is:
To find the sum of the coefficients in the expansion of \((x^2 - \frac{1}{3})^{199} \cdot (x^3 + \frac{1}{2})^{200}\), we can follow these steps: ### Step 1: Substitute \(x = 1\) To find the sum of the coefficients, we substitute \(x = 1\) into the expression. \[ (1^2 - \frac{1}{3})^{199} \cdot (1^3 + \frac{1}{2})^{200} \] ### Step 2: Simplify the expressions Now, simplify each part: 1. For \((1^2 - \frac{1}{3})^{199}\): \[ 1 - \frac{1}{3} = \frac{2}{3} \] So, \[ (1 - \frac{1}{3})^{199} = \left(\frac{2}{3}\right)^{199} \] 2. For \((1^3 + \frac{1}{2})^{200}\): \[ 1 + \frac{1}{2} = \frac{3}{2} \] So, \[ (1 + \frac{1}{2})^{200} = \left(\frac{3}{2}\right)^{200} \] ### Step 3: Combine the results Now, we combine the two results from above: \[ \left(\frac{2}{3}\right)^{199} \cdot \left(\frac{3}{2}\right)^{200} \] ### Step 4: Simplify the combined expression We can rewrite this as: \[ \frac{2^{199}}{3^{199}} \cdot \frac{3^{200}}{2^{200}} = \frac{2^{199} \cdot 3^{200}}{3^{199} \cdot 2^{200}} \] ### Step 5: Simplify further Now, simplify the expression: \[ = \frac{3^{200}}{3^{199}} \cdot \frac{2^{199}}{2^{200}} = \frac{3^{200}}{3^{199}} \cdot \frac{1}{2} = 3 \cdot \frac{1}{2} = \frac{3}{2} \] ### Final Answer Thus, the sum of the coefficients in the expansion is: \[ \frac{3}{2} \] ---
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